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⬤ NEWTON'S INVERSE SQUARE LAW — EXPLORER

3D GEOMETRIC PROOF · F vs r GRAPH · EQUAL FORCE AREA · CANDLE COMPARISON

🌐 3D SPHERES
📈 F vs r
⚖️ EQUAL FORCE
🕯️ CANDLE
⚙ Parameters
Spheres 4
2
3
4
5
6
Mass M 5.0×10²⁴kg
Base r₁ 1.0 AU
Highlight r₁
📊 Data
SpherergPatch
g = GM/r²
Patch A = Ω·r²
Same patch on all spheres
g·A = const ✓
👆 drag · pinch zoom · tap sphere
📡 Selected
FIELD g
m/s²
SURFACE AREA
AU²
🔴 PATCH AREA
Same size on every sphere
g×Area = const ✓
📐 Patch Compare
Key: The red patch is the same physical size on every sphere. g differs, but Force = g×Area stays constant — geometry explains 1/r².
⚙ Graph
Mass M 5.0×10²⁴
Test m 1.0 kg
Probe r 2.0 AU
r-max 10 AU
Overlays
CURVE
TANGENT
DOTS
AREA
2nd
GRID
F=GMm/r²
dF/dr=−2GMm/r³
d²F/dr²=+6GMm/r⁴
📍 At r=
F(r)
F=GMm/r²
Newtons
dF/dr
−2GMm/r³
N/AU
d²F/dr²
+6GMm/r⁴
N/AU²
🧮 Derivation
POWER LAW
F=GMm·r⁻²
1ST DERIV (power rule)
dF/dr=GMm·(-2)·r⁻³
2ND DERIV
d²F/dr²=+6GMm/r⁴
AT PROBE
move probe
⚖️ Equal Force
Target F₀ auto
Mass M 5.0×10²⁴
Test m 1.0 kg
Spheres 4
2
3
4
5
6
Base r₁ 1.0 AU
Overlays
PATCHES
LABELS
ARROWS
ANIM
GRID
A=F₀·r²/GM
A∝r² for same F
g∝1/r² → g·A=const
🎯 Target F₀
REQUIRED FORCE
Newtons per patch
Per-Sphere Areas
FORCE ON PATCH
F=g·A=GM/r²·A
SOLVE FOR AREA
A=F·r²/GM ∝ r²
RATIO
A(nr)/A(r)=
Key: To feel the same force at each sphere, the patch must grow as . This is the inverse-square law in reverse.
🕯️ Settings
Power I₀ 100
Max dist 8 m
Probe r 3.0 m
Overlays
FLAME
WAVES
LABELS
PROBE
BAR
GRID
E=I₀/r²
vs E=I₀/r
Sq: 2×→¼, 3×→1/9
Lin: 2×→½, 3×→1/3
Real light obeys 1/r²
INVERSE SQUARE E=I₀/r²
LINEAR LAW E=I₀/r (hypothetical)
📊 Comparison
INVERSE SQUARE E
I₀/r² lux
LINEAR E
I₀/r lux
LINEAR / INV.SQ. RATIO
Linear stays brighter at distance
Distance Table
Key: With 1/r², brightness collapses fast — at 4m already 1/16. With 1/r only 1/4. This is why stars look so dim!
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