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Ladder Friction

adjust θ · change μ · watch it slip

Equilibrium ✓
θ = 60°
N₁
N₂
f₁
f₂
W
Angle θ with floor
θ 60°
Floor friction μ₁
μ₁ 0.35
Wall friction μ₂
μ₂ 0.20
Mode
Critical θ
Forces (W=1)
N₁
N₂
f₁
Formulas
Both Rough
tan(θ) = (1−μ₁μ₂)/(μ₁+μ₂)
cot(θ) = (μ₁+μ₂)/(1−μ₁μ₂)
Wall Smooth (μ₂=0)
μ₁ = (1/2)·cot(θ)
Same Friction (μ₁=μ₂=μ)
μ = (1−sin θ)/cos θ
μ = sec θ − tan θ
Floor Smooth (μ₁=0)
No equilibrium possible
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