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sin(x + φ)
PHASE SHIFT φ
any°
±45
−360°+360°
AMPLITUDE A 1.00
0.13.0
FREQUENCY ω 1.00
0.1×T=2π
PHASE SHIFT EXPLORER · φ ∈ (−∞, +∞)
sin(x + φ)
sin(x + φ)
cos(x + φ)
Unit Circle
Arc Length
Small θ
+1 +0.5 0 −0.5 −1
φ shift
drag to rotate
PHASE ANGLE φ — any value
type any°
↑↓ = ±1
← drag left/right · scroll · unlimited →
PRESETS
FUNCTION
VALUE AT x=0
sin(φ)
PEAK AT x=
max = +1
EQUIVALENT
FULL CYCLES
0
× 360°
sin(x)
cos(x) ref
sin(x+φ)
+1 +0.5 0 −0.5 −1
φ shift
drag to rotate
PHASE ANGLE φ — any value
type any°
↑↓ = ±1
← drag left/right · scroll · unlimited →
PRESETS
FUNCTION
VALUE AT x=0
cos(φ)
PEAK AT x=
max = +1
EQUIVALENT
FULL CYCLES
0
× 360°
cos(x)
sin(x) ref
cos(x+φ)
+1 +0.5 0 −0.5 −1
−1 −0.5 0 +0.5 +1 ← cos(θ) = x →
↑ sin(θ) = y ↑
ANGLE θ (degrees — any value)
type any°
↑↓ = ±1
← drag left/right · scroll · unlimited →
NOTABLE ANGLES
▸ sin(θ) = y-coordinate (vertical)
+1 0 −1
▸ cos(θ) = x-coordinate (horizontal)
+1 0 −1
cos(θ) = x
1.000
horizontal projection
onto x-axis
sin(θ) = y
0.000
vertical projection
onto y-axis
θ (normalised)
within 0°–360°
full rotations
0
× 360°
IDENTITY AT THIS ANGLE
sin(0°)=0 · cos(0°)=1
▸ PHASE SHIFT INSIGHT
1
CHOOSE RADIUS r — YOUR CIRCLE (unit circle stays fixed at r=1)
2
CHOOSE ANGLE θ — drag the point on YOUR CIRCLE or use the wheel
60°
Arc length s = r·|θ| is always positive — drag CW to visualise clockwise rotation.
RADIUS r
1.000
ANGLE θ
60°
1.047 rad
↺ CCW
ARC s = r·|θ|
1.047
always ≥ 0
UNIT ARC s₁=θ
1.047
🔒 r=1 fixed → s=θ
KEY INSIGHT — s = r · θ
Both circles share the same angle θ. The unit circle arc s₁ = θ (numerically equal). Your circle arc s = r × s₁ — it scales by r.
ANGLE θ — drag slider
30.0°
SMALL ANGLE APPROXIMATIONS
sin θ ≈ θ
actual sin θ
approx θ
cos θ ≈ 1
actual cos θ
approx 1
1.00000
s = r·θ
arc s
chord
ARC IS NOW STRAIGHT!
Paused — look how the arc, chord & triangle base all coincide.
sin θ ≈ θ  ·  cos θ ≈ 1  ·  s = r·θ
🔍 ZOOM
① sin θ ≈ θ
The opposite side of the right triangle = r·sin θ.
When θ is tiny, the arc and the opposite side are nearly equal.
Since arc = r·θ, we get sin θ ≈ θ.
Taylor: sin θ = θ − θ³/6 + … ≈ θ
② cos θ ≈ 1
The adjacent side of the triangle = r·cos θ.
When θ → 0, the radius barely tilts — the horizontal projection stays ≈ r.
So cos θ ≈ 1 (next term: 1 − θ²/2).
Taylor: cos θ = 1 − θ²/2 + … ≈ 1
③ s = r · θ
Arc fraction of full circle:
s = 2πr · (θ/2π) = r · θ
When θ→0, chord ≈ arc ≈ r·θ,
so all three sides converge.
chord = 2r·sin(θ/2) ≈ rθ
ERROR TABLE (r=1)
θ sinθ err cosθ err arc err
<0.01%0.015%<0.001%
0.13%0.38%0.13%
10°0.51%1.52%0.51%
20°2.06%6.03%2.06%
30°4.72%13.4%4.72%
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